Optimal. Leaf size=83 \[ \frac{b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \tan (c+d x)}{\sqrt{a}}\right )}{\sqrt{a} d (a-b)^2}+\frac{\sin (c+d x) \cos (c+d x)}{2 d (a-b)}+\frac{x (a-3 b)}{2 (a-b)^2} \]
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Rubi [A] time = 0.103657, antiderivative size = 83, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.217, Rules used = {3675, 414, 522, 203, 205} \[ \frac{b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \tan (c+d x)}{\sqrt{a}}\right )}{\sqrt{a} d (a-b)^2}+\frac{\sin (c+d x) \cos (c+d x)}{2 d (a-b)}+\frac{x (a-3 b)}{2 (a-b)^2} \]
Antiderivative was successfully verified.
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Rule 3675
Rule 414
Rule 522
Rule 203
Rule 205
Rubi steps
\begin{align*} \int \frac{\cos ^2(c+d x)}{a+b \tan ^2(c+d x)} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right )^2 \left (a+b x^2\right )} \, dx,x,\tan (c+d x)\right )}{d}\\ &=\frac{\cos (c+d x) \sin (c+d x)}{2 (a-b) d}-\frac{\operatorname{Subst}\left (\int \frac{-a+2 b-b x^2}{\left (1+x^2\right ) \left (a+b x^2\right )} \, dx,x,\tan (c+d x)\right )}{2 (a-b) d}\\ &=\frac{\cos (c+d x) \sin (c+d x)}{2 (a-b) d}+\frac{(a-3 b) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\tan (c+d x)\right )}{2 (a-b)^2 d}+\frac{b^2 \operatorname{Subst}\left (\int \frac{1}{a+b x^2} \, dx,x,\tan (c+d x)\right )}{(a-b)^2 d}\\ &=\frac{(a-3 b) x}{2 (a-b)^2}+\frac{b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \tan (c+d x)}{\sqrt{a}}\right )}{\sqrt{a} (a-b)^2 d}+\frac{\cos (c+d x) \sin (c+d x)}{2 (a-b) d}\\ \end{align*}
Mathematica [A] time = 0.18469, size = 78, normalized size = 0.94 \[ \frac{4 b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \tan (c+d x)}{\sqrt{a}}\right )+\sqrt{a} (2 (a-3 b) (c+d x)+(a-b) \sin (2 (c+d x)))}{4 \sqrt{a} d (a-b)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.069, size = 137, normalized size = 1.7 \begin{align*}{\frac{{b}^{2}}{d \left ( a-b \right ) ^{2}}\arctan \left ({b\tan \left ( dx+c \right ){\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}}+{\frac{a\tan \left ( dx+c \right ) }{2\,d \left ( a-b \right ) ^{2} \left ( \left ( \tan \left ( dx+c \right ) \right ) ^{2}+1 \right ) }}-{\frac{b\tan \left ( dx+c \right ) }{2\,d \left ( a-b \right ) ^{2} \left ( \left ( \tan \left ( dx+c \right ) \right ) ^{2}+1 \right ) }}+{\frac{\arctan \left ( \tan \left ( dx+c \right ) \right ) a}{2\,d \left ( a-b \right ) ^{2}}}-{\frac{3\,\arctan \left ( \tan \left ( dx+c \right ) \right ) b}{2\,d \left ( a-b \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.68791, size = 690, normalized size = 8.31 \begin{align*} \left [\frac{2 \,{\left (a - 3 \, b\right )} d x + 2 \,{\left (a - b\right )} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \sqrt{-\frac{b}{a}} \log \left (\frac{{\left (a^{2} + 6 \, a b + b^{2}\right )} \cos \left (d x + c\right )^{4} - 2 \,{\left (3 \, a b + b^{2}\right )} \cos \left (d x + c\right )^{2} - 4 \,{\left ({\left (a^{2} + a b\right )} \cos \left (d x + c\right )^{3} - a b \cos \left (d x + c\right )\right )} \sqrt{-\frac{b}{a}} \sin \left (d x + c\right ) + b^{2}}{{\left (a^{2} - 2 \, a b + b^{2}\right )} \cos \left (d x + c\right )^{4} + 2 \,{\left (a b - b^{2}\right )} \cos \left (d x + c\right )^{2} + b^{2}}\right )}{4 \,{\left (a^{2} - 2 \, a b + b^{2}\right )} d}, \frac{{\left (a - 3 \, b\right )} d x +{\left (a - b\right )} \cos \left (d x + c\right ) \sin \left (d x + c\right ) - b \sqrt{\frac{b}{a}} \arctan \left (\frac{{\left ({\left (a + b\right )} \cos \left (d x + c\right )^{2} - b\right )} \sqrt{\frac{b}{a}}}{2 \, b \cos \left (d x + c\right ) \sin \left (d x + c\right )}\right )}{2 \,{\left (a^{2} - 2 \, a b + b^{2}\right )} d}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.65799, size = 149, normalized size = 1.8 \begin{align*} \frac{\frac{2 \,{\left (\pi \left \lfloor \frac{d x + c}{\pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (b\right ) + \arctan \left (\frac{b \tan \left (d x + c\right )}{\sqrt{a b}}\right )\right )} b^{2}}{{\left (a^{2} - 2 \, a b + b^{2}\right )} \sqrt{a b}} + \frac{{\left (d x + c\right )}{\left (a - 3 \, b\right )}}{a^{2} - 2 \, a b + b^{2}} + \frac{\tan \left (d x + c\right )}{{\left (\tan \left (d x + c\right )^{2} + 1\right )}{\left (a - b\right )}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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